Ch 2 · 3.5–3.7 Equations of Lines, Parallel and Perpendicular Lines · O Level Mathematics 4024
Topic 2 of 2 in Coordinate Geometry — O Level Mathematics 4024 — 56 lessons.
Introduction
Every straight line has an equation that tells you its steepness and where it crosses the y-axis. Once you can find that equation, you can find lines parallel to it (same direction) or perpendicular to it (at right angles), which is how roads, ramps and boundaries are designed. (Syllabus sections 3.5–3.7.)
Key ideas — y = mx + c
m is the gradient and c the y-intercept. Rearrange other forms to read them: 5x + 4y = 8 ⇒ y = -tfrac54x + 2, gradient -tfrac54, intercept 2. Vertical lines are x = k; horizontal lines y = k.
🧑🏫 Teacher's explanation
Think of a straight line as a path on a map. The gradient, m, tells you how steep the path is—whether you are climbing up a hill or sliding down into a valley. The y-intercept, c, is simply the starting height where the path crosses the vertical axis.
📖 Definitions
🔍 Worked example — Easy
Find the gradient and y-intercept of the line with equation 3x - 2y = 6.
🔍 Worked example — Standard
Find the equation of the line parallel to y = 4x - 1 that passes through the point (2, 5).
🔍 Worked example — Exam-style
Find the equation of the perpendicular bisector of the line segment joining A(2, 4) and B(6, 10).
⚠️ Common errors
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🎯 Exam question
Key ideas — Finding an equation
From a gradient m and a point (x_1, y_1): substitute into y = mx + c to find c (or use y - y_1 = m(x - x_1)). From two points: find m first. From a graph: read the intercept and measure the gradient. Give the final equation fully simplified, in the form asked.
🧑🏫 Teacher's explanation
Think of a straight line as a set of rules that tells every point (x, y) exactly where to stand. The 'gradient' m is the rule for how steep the line is—how much it rises for every step it moves forward. The 'y-intercept' c is simply the starting height where the line crosses the vertical axis.
📖 Definitions
🔍 Worked example — Easy
Find the equation of the line with gradient 3 that passes through the point (2, 5).
🔍 Worked example — Standard
Find the equation of the line perpendicular to y = 2/3x + 4 that passes through (4, 1).
🔍 Worked example — Exam-style
Find the equation of the perpendicular bisector of the line segment joining A(-2, 4) and B(4, 8).
⚠️ Common errors
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🎯 Exam question
Key ideas — Parallel lines
Parallel lines have equal gradients. The line parallel to y = 4x - 1 through (1, -3): -3 = 4(1) + c ⇒ c = -7, so y = 4x - 7.
🧑🏫 Teacher's explanation
Imagine you are walking up a staircase. If two staircases are built with the exact same steepness, they are parallel; no matter how far you walk along them, the distance between them stays exactly the same. In coordinate geometry, 'steepness' is what we call the gradient, denoted by m.
📖 Definitions
🔍 Worked example — Easy
Find the gradient of a line that is parallel to the line with equation y = -3x + 5.
🔍 Worked example — Standard
Find the equation of the line parallel to 2y = 6x + 4 that passes through the point (2, 5).
🔍 Worked example — Exam-style
Find the equation of the line parallel to 3x - 4y = 12 that passes through the point (-2, 1). Give your answer in the form ax + by = c.
⚠️ Common errors
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🎯 Exam question
Key ideas — Perpendicular lines
Perpendicular gradients multiply to -1:
🧑🏫 Teacher's explanation
Imagine two roads crossing each other at a perfect 90^° angle, like a crossroad in a city grid. If one road is climbing steeply, the road crossing it must be descending to maintain that perfect right angle. This relationship is captured by the gradients of the two lines.
📖 Definitions
🔍 Worked example — Easy
Find the gradient of a line that is perpendicular to the line with equation y = 4x - 7.
🔍 Worked example — Exam-style
Find the equation of the perpendicular bisector of the line segment joining A(2, 3) and B(6, 11).
⚠️ Common errors
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🎯 Exam question
Key ideas — Perpendicular bisector
The perpendicular bisector of AB passes through the midpoint of AB with gradient -dfrac1m_AB.
🧑🏫 Teacher's explanation
Imagine you are standing exactly halfway between two friends who are standing apart. If you want to walk in a direction that is perfectly 'square' or at a right angle to the line connecting them, you are walking along their perpendicular bisector. It is the unique path that stays exactly equidistant from both people.
📖 Definitions
🔍 Worked example — Standard
Find the equation of the perpendicular bisector of the line segment joining P(-3, 2) and Q(5, -2).
🔍 Worked example — Exam-style
The line segment joining A(k, 3) and B(4, 7) has a perpendicular bisector with the equation y = x + 1. Find the value of k.
⚠️ Common errors
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🎯 Exam question
Worked examples
Through (2, 5) and (6, 13): m = 8/4 = 2; 5 = 2(2) + c ⇒ c = 1; y = 2x + 1.
🔍 Worked example — Easy
Find the equation of the line passing through the points (2, 5) and (6, 13).
🔍 Worked example — Standard
Find the equation of the line parallel to y = 4x - 1 that passes through the point (1, -3).
🔍 Worked example — Exam-style
Find the equation of the perpendicular bisector of the line segment joining (-3, 8) and (9, -2).
⚠️ Common errors
Common mistakes
Practice
Answers: (1) y = tfrac32x - 6: gradient tfrac32, intercept -6. (2) y = -3x + 1. (3) y = -tfrac12x + 3. (4) midpoint (2, 4), gradient of AB is 1, so y = -x + 6.