Ch 4 · Isomerism: optical · AS & A Level Chemistry 9701
Topic 4 of 4 in An introduction to A Level organic chemistry — AS & A Level Chemistry 9701 — 48 lessons.
Introduction
AS Level introduced the chiral carbon and the idea of non-superimposable mirror-image enantiomers. A2 organic chemistry develops this into a quantitative and industrially important topic: how enantiomers are distinguished experimentally using polarised light, why racemic mixtures form, and why chirality is central to modern drug design, since a molecule's biological target is itself chiral.
Key ideas — Enantiomers: identical except in two respects
A pair of enantiomers are non-superimposable mirror images of each other, arising from a carbon atom bonded to four different groups (a chiral centre). Because enantiomers have the same atoms connected in the same way, differing only in the three-dimensional arrangement around the chiral centre, they share identical melting points, boiling points, densities and normal chemical reactivity with achiral reagents. They differ in exactly two respects: their effect on plane-polarised light, and their biological activity, since biological receptors, enzymes and transport proteins are themselves chiral and interact differently with each enantiomer, often binding only one of the pair effectively.
🧑🏫 Teacher's explanation
Imagine you are holding your hands up in front of your face, palms facing you. Your left hand is a mirror image of your right hand. No matter how you rotate your left hand, you can never make it perfectly overlap with your right hand (the thumb will always be on the wrong side). This is exactly what happens at the molecular level with enantiomers.
📖 Definitions
🔍 Worked example — Easy
A sample of a chiral compound contains 0.50 mol of the (+)-enantiomer and 0.50 mol of the (-)-enantiomer. What is the composition of this mixture in terms of percentage of each enantiomer?
🔍 Worked example — Standard
Explain why enantiomers have identical boiling points.
🔍 Worked example — Exam-style
A drug molecule has a chiral centre. One enantiomer is therapeutic, while the other is toxic. Why is it important for pharmaceutical companies to use chiral catalysts during synthesis?
⚠️ Common errors
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🎯 Exam question
(a) Define the term 'enantiomer'. [1] (b) Explain why the (+)-enantiomer of a drug might be effective in treating a disease, while the (-)-enantiomer might be harmful. [2] [3 marks]
Key ideas — Optical activity and rotation of plane-polarised light
Ordinary light vibrates in all planes perpendicular to its direction of travel; passing it through a polarising filter produces plane-polarised light, vibrating in a single plane. A substance is described as optically active if it rotates the plane of this light as it passes through a solution or the pure liquid, a property measured using a polarimeter. Of a pair of enantiomers, one rotates the plane of polarised light clockwise (dextrorotatory, denoted +) and the other rotates it anticlockwise by the exact same angle (laevorotatory, denoted −); this equal-and-opposite rotation is the only physical property that distinguishes them.
🧑🏫 Teacher's explanation
Imagine you are holding a long, thin stick and spinning it rapidly in all directions. This represents ordinary light, where the vibrations are chaotic and cover every possible angle. Now, imagine you pass that stick through a picket fence with vertical slats. Only the vibrations that are vertical can pass through. This is plane-polarised light; it is now vibrating in only one single plane.
📖 Definitions
🔍 Worked example — Easy
A sample of a chiral compound is placed in a polarimeter. It rotates plane-polarised light by +15^°. Identify the relationship between this sample and its enantiomer.
🔍 Worked example — Standard
A solution contains 2.0 g of a chiral substance in 50 cm^3 of solvent. If the observed rotation is +5.0^°, calculate the specific rotation [α] using the formula: specific rotation = θ/c · l, where θ is the observed rotation, c is concentration in g/cm^3, and l is path length in dm. Assume l = 1 dm.
🔍 Worked example — Exam-style
A drug molecule has two chiral centres. One enantiomer is biologically active and treats a disease, while the other is toxic. Explain why a manufacturer would use a chiral catalyst to synthesize this drug instead of standard chemical methods.
⚠️ Common errors
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🎯 Exam question
(a) Define the term 'racemic mixture'. [1] (b) Explain why the chemist observes no rotation of plane-polarised light when passing it through the sample. [2] (c) Suggest one method the chemist could use to produce only the desired enantiomer from a mixture. [1] [4 marks]
Key ideas — Racemic mixtures
A racemic mixture (racemate) is an equimolar (50:50) mixture of both enantiomers of a chiral compound. Although each enantiomer individually rotates plane-polarised light, their equal and opposite rotations exactly cancel in a racemic mixture, so it shows no net optical activity. Racemic mixtures commonly form whenever a reaction creates a new chiral centre by attack on a planar, non-chiral intermediate (such as a carbocation, or a flat carbon–oxygen double bond) from either face with equal probability, since there is no preference for either enantiomer to form.
🧑🏫 Teacher's explanation
Imagine you are holding a pair of gloves. Your left hand and your right hand are like enantiomers: they are mirror images that cannot be perfectly superimposed on each other. If you look at them individually, they are distinct. However, if you have a bag containing exactly one left glove and one right glove, and you try to measure the 'handedness' of the bag as a whole, the effects cancel out.
📖 Definitions
🔍 Worked example — Easy
A sample of a chiral compound contains 0.50 mol of the (+) enantiomer and 0.50 mol of the (-) enantiomer. Calculate the net rotation of plane-polarised light if the (+) enantiomer rotates light by +15^° and the (-) enantiomer rotates it by -15^°.
🔍 Worked example — Standard
A chemist synthesizes a chiral molecule from a planar carbonyl group using a non-chiral reagent. The resulting product is a racemic mixture. If the specific rotation [α] of the pure (R)-enantiomer is +40^°, what is the observed rotation of the racemic mixture?
🔍 Worked example — Exam-style
A drug molecule has a chiral centre. One enantiomer is effective at treating a disease, while the other is toxic. A reaction produces a racemic mixture of the drug. If the total mass of the mixture is 10.0 g and the molar mass of the drug is 200 g/mol, calculate the mass of the beneficial enantiomer in the mixture.
⚠️ Common errors
🧠 Quick check 1
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🎯 Exam question
(a) Explain why it is important for the drug to be produced as a single enantiomer rather than a racemic mixture. [2] (b) Describe how a chemist could use a chiral catalyst to ensure only one enantiomer is produced. [2] [4 marks]
Key ideas — Chirality in drug synthesis and chiral catalysts
Because biological receptors are chiral, the two enantiomers of a drug molecule can have very different effects: one enantiomer may bind its target and produce the desired therapeutic effect, while the other may be inactive, less active, or in some cases toxic. The drug thalidomide is a well-known example, where one enantiomer acted as an effective sedative while the other caused severe birth defects. A conventional synthesis that proceeds through a planar intermediate produces a racemic mixture, wasting half the product as the ineffective or harmful enantiomer and requiring costly separation. Chiral catalysts (including some enzymes and specially designed chiral transition-metal catalysts) solve this by providing an asymmetric environment that favours attack from one particular face of a planar intermediate, so the reaction produces predominantly, or exclusively, a single enantiomer. This asymmetric synthesis avoids the need to separate a racemate, increases the effective yield of the useful enantiomer, and reduces the risk of side effects from an unwanted isomer reaching patients.
🧑🏫 Teacher's explanation
Imagine you are trying to put a right-handed glove on your left hand. No matter how you turn it, it will never fit perfectly because the shape is 'handed'. In chemistry, many molecules are like this. They have a 'chiral center' (usually a carbon atom bonded to four different groups) that makes the whole molecule non-superimposable on its mirror image. These mirror-image pairs are called enantiomers.
📖 Definitions
🔍 Worked example — Easy
A sample of a chiral drug is found to rotate plane-polarised light by +15.0^°. A second sample of the same drug is prepared which is a racemic mixture. What is the observed rotation of the second sample?
🔍 Worked example — Standard
A chemist uses a chiral catalyst to synthesize a drug. The yield of the (R)-enantiomer is 8.5 g and the yield of the (S)-enantiomer is 1.5 g. Calculate the mass percentage of the desired (R)-enantiomer in the product mixture.
🔍 Worked example — Exam-style
A drug molecule has a molecular formula of C_3H_6Cl_2. One enantiomer rotates light by +α and the other by -α. If a sample contains 2.0 g of the (+) isomer and 2.0 g of the (-) isomer, calculate the observed rotation of the mixture.
⚠️ Common errors
🧠 Quick check 1
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🎯 Exam question
Worked example — Model answer
Question. A pure sample of one enantiomer of a chiral drug molecule has a specific rotation of +16^°. A synthesised sample of the same drug is found to have an observed rotation of +8^°.
🔍 Worked example — Easy
A sample of 2-chlorobutane shows an observed rotation of +5.0^°. If the pure (R)-enantiomer has a specific rotation of +10.0^°, calculate the enantiomeric excess (ee) of the sample.
🔍 Worked example — Standard
A mixture contains 0.50 g of the (+) enantiomer (rotation +20^°) and 0.50 g of the (-) enantiomer (rotation -20^°). What is the net observed rotation of the mixture?
🔍 Worked example — Exam-style
A drug molecule has two chiral centres. One enantiomer has a specific rotation of +40^°. A sample is prepared containing 80% of the (+) enantiomer and 20% of the (-) enantiomer. Calculate the observed rotation of this sample.
⚠️ Common errors
Common mistakes
Practice
Answers